[Nfd-dev] Question about std::chrono::duration conversion to/from time::duration

[Junxiao Shi]

Hi Alex

We can:

   - declare time::duration<Rep, Period> as a new class that inherits from
   boost::chrono::duration<Rep, Period>
   - in time::duration<Rep, Period>, provide an implicit conversion
   function to std::chrono::duration<Rep2, Period2>, and use enable_if to
   restrict the equivalence of Rep-Rep2 and Period-Period2
   - in time::duration<Rep, Period>, provide an implicit constructor from
   std::chrono::duration<Rep2, Period2>, and use enable_if to restrict the
   equivalence of Rep-Rep2 and Period-Period2


The alternate is:

   - typedef std::chrono::duration as time::duration
   - implement operator<<(std::ostream&, time::duration) overloads that
   prints the duration by internally converting to boost::chrono::duration


Yours, Junxiao

On Thu, Nov 13, 2014 at 3:25 PM, Alex Afanasyev <
alexander.afanasyev at ucla.edu> wrote:

>
> > On Nov 13, 2014, at 1:58 PM, Junxiao Shi <shijunxiao at email.arizona.edu>
> wrote:
> >
> > Dear folks
> >
> > Whether ndn::time is using boost::chrono or std::chrono shall be an
> implementation detail.
> > I think we should provide implicit conversion operators between
> ndn::time::duration<Rep,Period> and std::chrono::duration<Rep,Period>, when
> Rep is the same and Period is equivalent.
>
> Is there a way to do it without us creating our own class?  I don’t seem
> to find a simple way for that.  I really don’t want us to create duration
> class and implement everything that is implemented in std/boost::chrono
>
>
>
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